3(2cos^2(x)-1)-5cos(x)=0

Solution for 3(2cos^2(x)-1)-5cos(x)=0 equation:

Simplifying
3(2cos2(x) + -1) + -5cos(x) = 0

Multiply cos2 * x
3(2cos2x + -1) + -5cos(x) = 0

Reorder the terms:
3(-1 + 2cos2x) + -5cos(x) = 0
(-1 * 3 + 2cos2x * 3) + -5cos(x) = 0
(-3 + 6cos2x) + -5cos(x) = 0

Multiply cos * x
-3 + 6cos2x + -5cosx = 0

Reorder the terms:
-3 + -5cosx + 6cos2x = 0

Solving
-3 + -5cosx + 6cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + -5cosx + 3 + 6cos2x = 0 + 3

Reorder the terms:
-3 + 3 + -5cosx + 6cos2x = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -5cosx + 6cos2x = 0 + 3
-5cosx + 6cos2x = 0 + 3

Combine like terms: 0 + 3 = 3
-5cosx + 6cos2x = 3

Reorder the terms:
-3 + -5cosx + 6cos2x = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + -5cosx + 6cos2x = 0

The solution to this equation could not be determined.